210 210
Pb --> Bi + ?
82 83
60 0
Co --> ? + e
27 -1
I need an explanation on how to find the missing product.
The subscripts must add up on both sides. The superscripts must add up on both sides. For the first one, You start with Pb-210 and end with Bi=210; therefore, the ? particle must have a mass of zero since 210 + 0 on the right = 210 on the left. For the atomic number, you have 82Pb on the left and 83Bi on the right. Therefore, the ? particle must be -1 because 83 + (-1) = 82.
Now, what particle has a mass of zero and a charge of -1? Must be an electron. You replace ? with -1eo
To find the missing product in each given chemical equation, you need to determine the atomic numbers and charges of the elements involved. Based on this information, you can balance the equation.
Let's start with the first equation:
82 Pb --> 83 Bi + ?
To find the missing product, you need to determine the atomic number and charge of the missing element. In this case, the atomic number of lead (Pb) is 82, and the atomic number of bismuth (Bi) is 83.
Since lead is the reactant, it will not change its charge during the reaction, so the charge remains 0. Bismuth, being the product, also has a charge of 0.
Now, to determine the missing product, you need to find an element with an atomic number that is one higher than 83 (since bismuth has an atomic number of 83). The element with an atomic number of 84 is polonium (Po). Therefore, the missing product is polonium (Po).
The balanced equation would be:
82 Pb --> 83 Bi + 84 Po
Now, let's move on to the second equation:
60 Co --> ? + e⁻
27 -1
To find the missing product, you need to determine the atomic number and charge of the missing element. In this case, the atomic number of cobalt (Co) is 27.
Cobalt is a reactant and has an atomic number of 27, but it also has a charge of 0. The charge of cobalt will not change during the reaction.
The missing product has an atomic number of 0 and a charge of -1, indicating an electron (e⁻), which is the missing product.
The balanced equation would be:
60 Co --> 0 ? + 1 e⁻