How does HI(g) split up into H and I.
1. Does it collide with another HI(g) and energy is lost? or the electron being shared gets dislocated?
2. If so then, can HI collide with anything ( H, I, the wall) to break down into H and I?
Nvm, i think i figured it out. HI has to collide with HI to form diatomic H2 and I2. Sorry about multiple posts.
http://www.colby.edu/chemistry/PChem/homework/Handin4.pdf
When HI(g) splits up into H and I, it typically involves a chemical reaction called dissociation. This process can occur through a variety of mechanisms, but the most common one is through the collision of HI(g) molecules with another species.
1. Collision-induced dissociation: In this mechanism, HI(g) molecule collides with another molecule or atom, transferring energy and disrupting the bond between hydrogen (H) and iodine (I). This collision can cause the bond to break, resulting in the formation of separate H and I atoms. The energy lost during the collision is released as kinetic energy and can contribute to the overall reaction.
2. HI can potentially collide with other molecules or atoms to undergo dissociation. However, not all collisions will lead to dissociation. For example, HI might collide with another HI molecule, but without sufficient energy transfer, the bond may not break, and dissociation will not occur. Similarly, colliding with a wall would unlikely provide the necessary conditions for dissociation.
In summary, the dissociation of HI(g) into H and I typically involves collision-induced dissociation, where an energetic collision with another species disrupts the bond between the hydrogen and iodine atoms.