Write the equation for the dissolution of (NH4)2S04 in water. How many moles of each type of ion, and how many total moles of ions does the dissolution of 0.5 mol of (NH4)2S04 produce? help pleaseeeeee ASAP
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(NH4)2SO4 ==> 2NH4^+ + SO4^-2
0.5 mole (NH4)2SO4 must produce 1. mole NH4^+ (2 x 0.5 = 1.)and 0.5 mole SO4^-2
The dissolution of (NH4)2SO4 can be represented by the chemical equation:
(NH4)2SO4 (s) → 2NH4+ (aq) + SO4^2- (aq)
In this equation, the solid (NH4)2SO4 dissociates into two ions: ammonium (NH4+) and sulfate (SO4^2-).
Since one mole of (NH4)2SO4 dissociates into two moles of NH4+ and one mole of SO4^2-, the dissolution of 0.5 mol of (NH4)2SO4 will produce:
- 2 x 0.5 mol = 1 mol of NH4+ ions
- 1 x 0.5 mol = 0.5 mol of SO4^2- ions
Thus, the total number of moles of ions produced is 1 mol + 0.5 mol = 1.5 mol.
Please note that the equation assumes complete dissociation of (NH4)2SO4 in water. In reality, there may be some degree of ion pairing or slight variation based on the conditions.
The dissolution equation for (NH4)2SO4 in water can be written as:
(NH4)2SO4 → 2NH4+ + SO42-
This equation shows that (NH4)2SO4 dissociates into two ammonium ions (NH4+) and one sulfate ion (SO42-).
To find out how many moles of each type of ion are produced, we need to consider the coefficients in the balanced equation.
For every one mole of (NH4)2SO4 that dissolves, it produces 2 moles of NH4+ ions and 1 mole of SO42- ions.
Since you have 0.5 mol of (NH4)2SO4, we can calculate the number of moles of each type of ion:
Number of moles of NH4+ ions = 2 moles NH4+ ions/mol (NH4)2SO4 × 0.5 mol (NH4)2SO4 = 1 mol NH4+ ions
Number of moles of SO42- ions = 1 mole SO42- ions/mol (NH4)2SO4 × 0.5 mol (NH4)2SO4 = 0.5 mol SO42- ions
To find the total moles of ions produced:
Total moles of ions = moles of NH4+ ions + moles of SO42- ions
= 1 mol NH4+ ions + 0.5 mol SO42- ions
= 1.5 mol of ions
Therefore, the dissolution of 0.5 mol of (NH4)2SO4 produces 1 mol of NH4+ ions, 0.5 mol of SO42- ions, and a total of 1.5 mol of ions in total.