how do you make 1.00g of NaC2H3O2 using:
0.400 M Na2Co3
0.300 M Pb(C2H3O2)2
NaOH solution with unknown molarity
0.500 M HC2H3O2
You don't have to use all of them
HC2H3O2 + NaOH ==> NaC2H3O2 + H2O
How many moles is 1 g NaC2H3O2. That is g/molar mass = 1g/82 = 0.0122 moles.
How can we get 0.0122 moles HC2H3O2.
M = moles/L or L = moles/M = 0.0122/0.5 = 0.02440L or 24.40 mL of 0.5M HC2H3O2. Then dump in NaOH until all of it is neutralized. You could add a drop of phenolphthalein to make sure you had enough NaOH (and if the pink color of the phenolphthalein is off limits you could use phenolphthalein as an outside indicator OR you could add NaOH until the indicator changes to slight pink, add a drop of acetic acid to make it the slightest acid to make the pink color change back to colorless).