# linear programming app

solve this linear programming problem;

A chain saw requires 4 hours of assembly and a wood chipper 6 hours. A maximum of 48 hours of assembly time is available. The profit is \$150 on a chain saw and \$220 on a chipper. How many of each should be assembled for maximum profit??

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1. Let C=chipper, S=chain saw
Objective function:
P(S,C)=150S + 220C
Constraints:
C≥0
S≥0
4S+6C≤48
There are three straight lines, so check the three intersections for the maximum values of the profit=P(S,C).

I see assembling chain-saws a little more profitable than chippers.

By the way, lady math tutors devote their time here too!

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