linear programming app

solve this linear programming problem;

A chain saw requires 4 hours of assembly and a wood chipper 6 hours. A maximum of 48 hours of assembly time is available. The profit is $150 on a chain saw and $220 on a chipper. How many of each should be assembled for maximum profit??

Thanks in advance guys!! =]

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  1. Let C=chipper, S=chain saw
    Objective function:
    P(S,C)=150S + 220C
    Constraints:
    C≥0
    S≥0
    4S+6C≤48
    There are three straight lines, so check the three intersections for the maximum values of the profit=P(S,C).

    I see assembling chain-saws a little more profitable than chippers.

    By the way, lady math tutors devote their time here too!

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