Calculate the mass of H2O produced by the decomposition of 2.21g of CuCO3 x Cu (OH)2. What happend to this water?

This question is incredibly important and I am stuck on it, thank you very much for your help

I might be able to help if I knew more about what you were doing. What follows is my guess of what you are doing.

I would write the equation as follows:
CuCO3.Cu(OH)2 --> 2CuO + CO2 + H2O
Here is a link to show you how to calculate the mass water produced.
http://www.jiskha.com/science/chemistry/stoichiometry.html
Where does the water go? If you are decomposing the compound, the water must have evaporated under the heat required for the decomposition. If I have guessed wrong as to what you are doing, please repost (a new post at the top of the first page) and provide more information.

32.87

Well, isn't water quite the H2Oxy moron? Alright, let's calculate the mass of water produced by the decomposition of CuCO3 x Cu(OH)2 and then dive into what happens to it.

To find the mass of water (H2O) produced, we need to first determine the molar mass of CuCO3 x Cu(OH)2.

CuCO3 has a molar mass of 123.55 g/mol, and Cu(OH)2 has a molar mass of 97.56 g/mol.

Now, let's do some math magic:

Molar mass of CuCO3 x Cu(OH)2 = (1 mol of CuCO3) + (1 mol of Cu(OH)2)
= (123.55 g/mol) + (97.56 g/mol)
= 221.11 g/mol

Given that we have 2.21 g of CuCO3 x Cu(OH)2, we can find the number of moles using the formula:

moles = mass / molar mass

moles = 2.21 g / 221.11 g/mol
= 0.01 mol

Now, according to the balanced equation, the decomposition of CuCO3 x Cu(OH)2 produces one mole of water for every one mole of CuCO3 x Cu(OH)2. So, the molar ratio of water to CuCO3 x Cu(OH)2 is 1:1.

Therefore, the mass of water produced is also 0.01 mol.

As for what happens to this water, well, it usually vaporizes into the air like a magician's disappearing act. However, in the real world, if the reaction is carried out in a closed system, the water might condense back into a liquid form once it cools down. So, it could end up as a liquid or a gas, depending on the conditions.

Hope that helps! Don't hesitate to ask if you have any more questions.

To calculate the mass of H2O produced by the decomposition of CuCO3 x Cu(OH)2, we need to first determine the chemical equation for the reaction.

CuCO3 x Cu(OH)2 decomposes when heated to form CuO (Copper(II) oxide) and H2O (Water).

The balanced chemical equation is:
CuCO3 x Cu(OH)2 -> CuO + H2O

From the equation, we can see that for every molecule of CuCO3 x Cu(OH)2 decomposed, one molecule of H2O is produced.

Now, we need to calculate the number of moles of CuCO3 x Cu(OH)2 and then convert that to moles of H2O.

Step 1: Calculate the number of moles of CuCO3 x Cu(OH)2.
To calculate the number of moles, we will use the formula:
Number of moles = Mass / Molar mass

The molar mass of CuCO3 x Cu(OH)2 can be calculated by adding up the molar masses of its individual elements:
Molar mass of CuCO3 x Cu(OH)2 = (1 x atomic mass of Cu) + (1 x atomic mass of C) + (3 x atomic mass of O) + (1 x atomic mass of Cu) + (1 x atomic mass of O) + (2 x atomic mass of H)

Step 2: Convert moles of CuCO3 x Cu(OH)2 to moles of H2O.
Since the balanced equation shows that the ratio of moles of CuCO3 x Cu(OH)2 to moles of H2O is 1:1, the number of moles of H2O produced will be the same as the number of moles of CuCO3 x Cu(OH)2.

Step 3: Calculate the mass of H2O produced.
To calculate the mass of H2O, we will use the formula:
Mass = Number of moles of H2O x Molar mass of H2O

Finally, it is important to clarify that the water produced in this reaction is in the gaseous state. It will be released as steam or water vapor when the CuCO3 x Cu(OH)2 decomposes.

Please provide the molar masses (atomic masses) of Cu, C, O, and H, and I can help you with the calculations.