If a term paper consisted 42 pages, each containing 40 lines of 100 symbols each (counting each space as a symbol), was to be encoded using Unicode, how many bytes of storage space would be required?
To calculate the number of bytes required to store the term paper, we need to consider the number of characters per page, the Unicode encoding used, and the size of each character in bytes.
First, let's calculate the number of characters on each page:
- 40 lines per page, each containing 100 symbols (including spaces) = 40 * 100 = 4000 symbols per page.
However, since we are counting each space as a symbol, we need to take that into account when calculating the number of characters. Let's assume that each symbol takes an average of 1 byte of storage:
- Total symbols per page = 4000
- Total spaces per page = 40 lines * 100 symbols = 4000 spaces
- Total characters per page = Total symbols per page + Total spaces per page = 4000 + 4000 = 8000 characters
Next, consider the encoding used. Unicode uses different encoding schemes, with UTF-8, UTF-16, and UTF-32 being the most common. Each encoding scheme has a different size for each character:
- UTF-8: 1 to 4 bytes per character
- UTF-16: 2 or 4 bytes per character
- UTF-32: 4 bytes per character
To determine the number of bytes required, we need to know which Unicode encoding scheme is being used. Let's assume we are using UTF-8, where each character takes 1 to 4 bytes.
Since we don't know the specific characters used in the term paper, we can estimate the average character size to be 2 bytes.
- Total characters = 8000 characters
- Estimated average size per character = 2 bytes
Finally, we can calculate the total storage space required:
- Total bytes required = Total characters * Estimated average size per character
= 8000 characters * 2 bytes
= 16000 bytes
Therefore, approximately 16,000 bytes of storage space would be required to store the term paper.