find the range of each function when the domain is {-3,-1.5,0,1,4}
r=4t^2+5
Just plug in each of those values for t to get the range.
To find the range of the function r = 4t^2 + 5, we need to substitute the given values of the domain into the function and determine the resulting range of values.
Let's start by substituting each value from the domain into the function:
For t = -3:
r = 4(-3)^2 + 5
r = 4(9) + 5
r = 36 + 5
r = 41
For t = -1.5:
r = 4(-1.5)^2 + 5
r = 4(2.25) + 5
r = 9 + 5
r = 14
For t = 0:
r = 4(0)^2 + 5
r = 4(0) + 5
r = 0 + 5
r = 5
For t = 1:
r = 4(1)^2 + 5
r = 4(1) + 5
r = 4 + 5
r = 9
For t = 4:
r = 4(4)^2 + 5
r = 4(16) + 5
r = 64 + 5
r = 69
Now we have the range of values for the function r for each value in the given domain:
When t = -3, r = 41
When t = -1.5, r = 14
When t = 0, r = 5
When t = 1, r = 9
When t = 4, r = 69
Therefore, the range of the function when the domain is {-3,-1.5,0,1,4} is {41, 14, 5, 9, 69}.