write the products of these combination reactions:
K + O2 --->
Ca + S --->
F2 + Al --->
To predict the products of these combination reactions, you need to consider the valence (oxidation) numbers of the elements involved.
1. K + O2 ---> To determine the product, we need to find the valence numbers of potassium (K) and oxygen (O). Potassium has a valence number of +1, while oxygen has a valence number of -2. In this reaction, potassium (K) will lose one electron and oxygen (O) will gain two electrons to achieve stability. Thus, the products of this reaction are potassium oxide (K2O).
2. Ca + S ---> To predict the product, we need to find the valence numbers of calcium (Ca) and sulfur (S). Calcium has a valence number of +2, while sulfur has a valence number of -2. In this reaction, calcium (Ca) will lose two electrons and sulfur (S) will gain two electrons to achieve stability. Hence, the products of this reaction are calcium sulfide (CaS).
3. F2 + Al ---> To determine the product, we need to find the valence numbers of fluorine (F) and aluminum (Al). Fluorine has a valence number of -1, while aluminum has a valence number of +3. In this reaction, fluorine (F) will gain one electron, and aluminum (Al) will lose three electrons to attain stability. Therefore, the product of this reaction is aluminum fluoride (AlF3).
By considering the valence numbers and the transfer of electrons in these combination reactions, we can predict the products as potassium oxide (K2O), calcium sulfide (CaS), and aluminum fluoride (AlF3).