A game of darts involves throwing two darts at the board. Hitting a blue region with a dart scores 1 point; a red region, 2 points, a green region, 3 points, and the orange region, 5 points.

Assume that no skill is involved. What is the probability, stated as a fraction in lowest terms, that two randomly thrown darts will score 8 points or more? Justify your answer.

You have 5-red, 3-green, 7-blue, 1-orange

I repeat my previous answer. You have not sufficiently defined the problem

To find the probability that two randomly thrown darts will score 8 points or more, we first need to calculate the different ways we can score 8 points or more.

The possible combinations that sum to 8 or more are:
- 5 + 3: This combination can be obtained by scoring 2 points on a red region and 3 points on a green region.
- 5 + 1 + 1: This combination can be obtained by scoring 2 points on a red region and 1 point on each of two blue regions.
- 3 + 3 + 2: This combination can be obtained by scoring 3 points on a green region and 2 points on another green region.
- 3 + 2 + 1 + 1: This combination can be obtained by scoring 3 points on a green region and 1 point on each of a red region and two blue regions.
- 2 + 2 + 2 + 2: This combination can be obtained by scoring 2 points on each of four red regions.

Now, we need to find the total number of possible outcomes when throwing two darts. In this case, there are a total of 16 regions (5 red, 3 green, 7 blue, and 1 orange), and each dart can land in any of these regions. Hence, the total number of possible outcomes is 16 * 16 = 256.

Next, we need to find the number of favorable outcomes, i.e., the number of combinations that add up to 8 points or more. From the earlier analysis, we found that there are 5 possible combinations. Therefore, the number of favorable outcomes is 5.

Finally, we can calculate the probability by dividing the number of favorable outcomes by the total number of possible outcomes. So, the probability is 5/256.

To express the probability as a fraction in its lowest terms, we can simplify the numerator and denominator. In this case, 5 and 256 do not have any common factors other than 1. Hence, the probability remains as 5/256 in its lowest terms.

Therefore, the probability, stated as a fraction in lowest terms, that two randomly thrown darts will score 8 points or more is 5/256.