A skater is gliding along the ice at 2.2 , when she undergoes an acceleration of magnitude 1.2 for 3.0 . At the end of that time she is moving at 5.8
Your numbers require dimensions. That is one of the first things a physics class should teach you.
One way of stating the problem correctly would be:
A skater is gliding along the ice at 2.2 m/s, when she undergoes an acceleration of magnitude 1.2 m/s^2 for 3.0 seconds. At the end of that time she is moving at 5.8 m/s.
That would be a statement of fact and not a question. They already provide the correct final velocity.
To find the displacement of the skater, we can use the equation of motion:
vf = vi + at
Where:
vf = final velocity = 5.8 m/s
vi = initial velocity = 2.2 m/s
a = acceleration = 1.2 m/s^2
t = time = 3.0 s
First, rearrange the equation to solve for displacement (d):
d = (vf - vi) / 2 * a * t^2
Plug in the given values:
d = (5.8 - 2.2) / 2 * 1.2 * (3.0)^2
Solve the equation:
d = 3.6 / 2 * 1.2 * 9
d = 3.6 / 21.6
d = 0.1667 m
Therefore, the displacement of the skater after 3 seconds is approximately 0.1667 meters.