HOW DO I Calculate the pKa of each acid.

C2O4H2, Ka = 5.9 10-2

Do you remember how to do pH?

pH = -log(H^+).
pKa is the same thing.
pKa = -log(Ka)
pKw = -log(Kw)
pKb = -log(Kb)

To calculate the pKa of an acid, you need to know the value of Ka, which is the acid dissociation constant. The pKa is simply the negative logarithm (base 10) of the Ka. Here's how you can calculate it for the acid C2O4H2 with a given Ka of 5.9 * 10^-2.

Step 1: Write down the equation for the dissociation of the acid:

C2O4H2 ⇌ C2O4 2- + H+

Step 2: Identify the concentration of the acid that can dissociate. Since it's not given in the question, assume it is 1 mol/L (you can use any concentration as long as you are consistent throughout the problem).

Step 3: Set up the expression for the acid dissociation constant (Ka):

Ka = [C2O4 2-] * [H+] / [C2O4H2]

Step 4: Substitute the given value of Ka and the concentration of the acid into the equation:

5.9 * 10^-2 = [C2O4 2-] * [H+] / 1

Step 5: Solve the equation for [C2O4 2-] * [H+]:

[C2O4 2-] * [H+] = 5.9 * 10^-2

Step 6: Take the square root of both sides to get the concentration of H+ (assuming equal concentrations of [C2O4 2-] and [H+]):

[H+] = √(5.9 * 10^-2)

Step 7: Substitute the concentration of H+ into the following expression:

pKa = -log10([H+])

pKa = -log10(√(5.9 * 10^-2))

Step 8: Calculate pKa using a calculator:

pKa ≈ 1.23

Therefore, the pKa of the acid C2O4H2 is approximately 1.23.