The freshman class is building a float for homecoming.One side of the float has a shape of a parallelogram with base of 12' and height of 6'. To complete the float the class must buy tissue to cover the side. It takes 3 boxes of tissue to cover each foot. If each box costs $ 0.50, what's the total cost of tissue to cover one side?
A B= bh = 12 * 6 = 72ft^2,
sqrt(72) = 8.48ft,
T = 8.48FT * 3Boxes/Ft = 25.5 Boxes,
C = 25.5boxes * 0.50/box = $12.73.
Please disregard the above post. The
analysis is incorrect.
To find the total cost of tissue to cover one side of the float, we need to calculate the area of the parallelogram first. The area of a parallelogram is given by the formula: area = base × height.
Given that the base of the parallelogram is 12' and the height is 6', we can substitute these values into the formula to find the area:
Area = 12 × 6 = 72 square feet.
Now, we need to determine how many boxes of tissue are needed to cover this area. It takes 3 boxes of tissue to cover each foot, so we can multiply the area of the parallelogram by 3 to find the total number of boxes required:
Total boxes = 72 × 3 = 216 boxes.
Each box of tissue costs $0.50, so to find the total cost, we can multiply the number of boxes by the cost per box:
Total cost = 216 × $0.50 = $108.
Therefore, the total cost of tissue to cover one side of the float is $108.