How many grams of Na2CO3 are required to Na2S2O3
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why react na2s2o3.5h20 with na2co3
To determine the number of grams of Na2CO3 required to react with Na2S2O3, you need to use the balanced chemical equation for the reaction between these two compounds.
The balanced chemical equation between Na2CO3 (sodium carbonate) and Na2S2O3 (sodium thiosulfate) is:
Na2CO3 + Na2S2O3 → 2Na2SO3 + CO2
From the equation, it is clear that one mole of sodium carbonate (Na2CO3) reacts with one mole of sodium thiosulfate (Na2S2O3), producing two moles of sodium sulfite (Na2SO3) and one mole of carbon dioxide (CO2).
To calculate the number of grams of Na2CO3 required, you need to know the molar mass of Na2CO3, which can be found by adding up the atomic masses of each element in the compound.
The atomic masses of sodium (Na), carbon (C), and oxygen (O) are approximately 23 g/mol, 12 g/mol, and 16 g/mol, respectively. Since there are two sodium atoms, one carbon atom, and three oxygen atoms in Na2CO3, the molar mass is:
2(23) + 12 + 3(16) = 46 + 12 + 48 = 106 g/mol
Now, you need to know the amount of Na2S2O3 you have and convert it to moles. Suppose you have 'x' grams of Na2S2O3. You can convert grams to moles using the molar mass of Na2S2O3.
The molar mass of Na2S2O3, which consists of two sodium atoms (2 × 23 g/mol), two sulfur atoms (2 × 32 g/mol), and three oxygen atoms (3 × 16 g/mol), is:
2(23) + 2(32) + 3(16) = 46 + 64 + 48 = 158 g/mol
So, the number of moles of Na2S2O3 is:
x grams * (1 mol / 158 g) = x / 158 moles
According to the balanced chemical equation, one mole of Na2CO3 reacts with one mole of Na2S2O3. Therefore, the number of moles of Na2CO3 required is also x / 158 moles.
Finally, to convert moles of Na2CO3 to grams, multiply by the molar mass of Na2CO3:
(x / 158 moles) * (106 g/mol) = (x * 106) / 158 grams
Therefore, (x * 106) / 158 grams of Na2CO3 are required to react with x grams of Na2S2O3.