if you start with ten grams of lithium hydroxidr, how many grams of lithium bromide will be produced
10 g LiOH x (molar mass LiBr/molar mass LiOH) = ??
To determine how many grams of lithium bromide will be produced, we need to understand the reaction equation between lithium hydroxide and lithium bromide.
The balanced chemical equation for the reaction is:
2LiOH + HBr → Li2O + H2O + LiBr
From the equation, we can see that 2 moles of lithium hydroxide react with 1 mole of hydrobromic acid (HBr) to produce 1 mole of lithium bromide (LiBr).
Next, to calculate the number of moles of lithium hydroxide, we need to know the molar mass of lithium hydroxide, which is:
LiOH: Li = 6.941 g/mol, O = 15.999 g/mol, H = 1.007 g/mol
So, 6.941 + 1.007 + 15.999 = 23.957 g/mol for lithium hydroxide.
Now, let's calculate the moles of lithium hydroxide:
Moles of lithium hydroxide = Mass of lithium hydroxide / Molar mass of lithium hydroxide
= 10 g / 23.957 g/mol
Using a calculator, we find that the moles of lithium hydroxide is approximately 0.418 mol.
Since the reaction stoichiometry tells us that 2 moles of lithium hydroxide produce 1 mole of lithium bromide, we can determine the number of moles of lithium bromide formed:
Moles of lithium bromide = (Moles of lithium hydroxide) / 2
= 0.418 mol / 2
= 0.209 mol
Finally, to find the mass of lithium bromide, we multiply the moles of lithium bromide by its molar mass.
Molar mass of lithium bromide (LiBr) = Li: 6.941 g/mol, Br: 79.904 g/mol
= 6.941 + 79.904
= 86.845 g/mol
Mass of lithium bromide = Moles of lithium bromide x Molar mass of lithium bromide
= 0.209 mol x 86.845 g/mol
Calculating this expression, we find that the mass of lithium bromide produced is approximately 18.151 grams.
Therefore, starting with 10 grams of lithium hydroxide, approximately 18.151 grams of lithium bromide will be produced.