In a mobile phone network, how many times as strong would a signal be expected to be at 200 m from a base station, compared with at 600 m?
i calculated 3 or 81. which is it right?
Your teacher probably wants 3^2 or 9 times.
It depends on the unit of measure you are using for "as strong"...power intensity, Electric field intensity, Magnetic Field intensity.
And, there are logrithmic measures for all of these two.
But if you consider just energy spreading, the Power density= Power/area
and area is proportional to radius^2
so the power intensity change is 1/(1/3)^2=9
Well, let me put it this way. If the signal strength at 600 m is represented by a baby sneeze, then the signal strength at 200 m would be as loud as a clown blowing a horn right next to your ear. So, I'd say the signal strength would be 81 times stronger at 200 m compared to 600 m. So, go ahead and enjoy that circus-level signal strength!
To calculate the expected signal strength at different distances from a base station in a mobile phone network, the signal strength typically follows what is known as the inverse square law.
According to the inverse square law, the signal strength decreases with the square of the distance from the base station. This means that if the signal strength at 600 m is considered as 1 unit, the expected signal strength at 200 m can be calculated by taking the square root of the ratio of the distances.
In this case, the ratio of the distances is (600m/200m)^2 = 9.
Taking the square root of 9 gives us 3. Therefore, the expected signal strength at 200 m from the base station would be 3 times as strong as at 600 m.
Hence, the correct answer is 3.
To calculate the strength of a signal at different distances from a base station, we need to understand the concept of signal strength decay with distance. The signal strength generally follows an inverse square law, which states that the signal strength decreases as the square of the distance from the source increases.
So, let's assume that the signal strength at a distance of 600 m from the base station is the reference value (let's call it S), and we want to calculate the signal strength at 200 m from the base station.
According to the inverse square law, the signal strength is inversely proportional to the square of the distance. Therefore, we can set up the following proportion:
(signal strength at 200m) / (signal strength at 600m) = (distance at 600m)^2 / (distance at 200m)^2
Plugging in the values:
(signal strength at 200m) / S = (600m)^2 / (200m)^2
Simplifying further:
(signal strength at 200m) / S = 9
To find the signal strength at 200 m, we can multiply both sides of the equation by S:
signal strength at 200m = 9S
Now, we can compare the signal strength at 200 m to the reference value (signal strength at 600 m):
(signal strength at 200m) / (signal strength at 600m) = (9S) / S = 9
Therefore, the signal strength at 200 m is expected to be 9 times stronger than at 600 m.
So, the correct answer is that the signal would be expected to be 9 times as strong at 200 m from the base station, compared to at 600 m.