# CHEM

kind of need some guidance with "PART C" below:

A) The bond angles in CH4 are 109.5degrees, while the bond angles in NH3 are 107 degrees.
Based on this information, which type of repulsion must be greater:

BP-BP

LP-BP

((((for this part I got: "LP-BP" as the correct answer))))

&

B) The bond angles in NH3 are 107degrees, while the bond angles in H2O are 105degrees. Based on this information, which type of repulsion must be greater?

LP-BP

LP-LP

((((for this part I got "LP-LP" as the correct answer))))

What I need help with, however, is:

C) Based on your answers to Parts A and B, arrange the three types of repulsion in order of increasing magnitude:

i) LP-BP < BP-BP < LP-LP

ii)BP-BP < LP-LP < LP-BP

iii) LP-LP < LP-BP < BP-BP

iv) BP-BP < LP-BP < LP-LP

----I think that the correct order should be: BP-BP < LP-BP < LP-LP
Is this correct??? Bonded-Bonded pairs sould not have a lot of repulsion if there are no lone pairs, correct??? Then as I asnwered in Part A - LP-BP & then as I asnwered in Part B - LP-LP???

& how can I tell/know for certain??? Any help is HUGELY appreciated!!

(BP = bonded pair LP = lone pair)

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1. I got the answer correct!!...It was BP-BP < LP-BP < LP-LP

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2. right. The answer I posted earlier is the opposite of what you have BUT I labeled it differently; i.e., from high to low.

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