I kind of need some guidance with "PART C" below:
A) The bond angles in CH4 are 109.5degrees, while the bond angles in NH3 are 107 degrees.
Based on this information, which type of repulsion must be greater:
BP-BP
LP-BP
((((for this part I got: "LP-BP" as the correct answer))))
&
B) The bond angles in NH3 are 107degrees, while the bond angles in H2O are 105degrees. Based on this information, which type of repulsion must be greater?
LP-BP
LP-LP
((((for this part I got "LP-LP" as the correct answer))))
What I need help with, however, is:
C) Based on your answers to Parts A and B, arrange the three types of repulsion in order of increasing magnitude:
i) LP-BP BP-BP LP-LP
BP-BP LP-LP LP-BP
LP-LP LP-BP BP-BP
BP-BP LP-BP LP-LP
& how can I tell/know for certain??? Any help is HUGELY appreciated!!
(BP = bonded pair LP = lone pair)
lp/lp >> lp/bp > bp/bp
To determine the order of increasing magnitude for the three types of repulsion (LP-BP, BP-BP, LP-LP), you can compare the bond angles in each scenario and consider the repulsive forces involved. Here's how you can approach it:
1) Let's start by reviewing the earlier information:
- In part A, you correctly determined that LP-BP repulsion is greater than BP-BP repulsion in NH3 (ammonia).
- In part B, you correctly determined that LP-LP repulsion is greater than LP-BP repulsion in H2O (water).
2) Now, let's consider how the repulsions in part A and part B can help us arrange the three types of repulsion in order of increasing magnitude in part C:
- Based on the information from part A, LP-BP repulsion is greater than BP-BP repulsion in NH3. Therefore, we know that LP-BP repulsion should be the greatest among the three types.
- Based on the information from part B, LP-LP repulsion is greater than LP-BP repulsion in H2O. However, we also know from part A that LP-BP repulsion in NH3 is greater than BP-BP repulsion. Therefore, LP-LP repulsion in H2O must be greater than BP-BP repulsion.
- Combining the above information, we can arrange the three types of repulsion in increasing order of magnitude as follows: BP-BP < LP-BP < LP-LP.
Therefore, the correct arrangement in part C is:
BP-BP < LP-BP < LP-LP
Remember, this reasoning is based on the information provided in parts A and B. By examining the bond angles associated with different molecules (NH3 and H2O) and considering the types of repulsion involved, you can determine the appropriate order.