Hi,
Can someone please confirm the following for me ..
This realtes to PSK or phase shift keying.
Is it right that 8PSK uses eight different phase shifts each representing one of the eight patterns of three bits ... ??
Does it ehn follow that 256PSK uses 256 different phase shifts each representing one of the 256 patterns of eight bits ???
I base this assumption on ..
2 4 8 16 32 64 128 256
1 2 3 4 5 6 7 8 bits
Can you please confirm I am right ?
Thank you for your help
Oddie
You are right, but apparently 8PSK is the highest used, because the error-rate beyond that increases faster than the benefit.
To quote from the reference below:
"Any number of phases may be used to construct a PSK constellation but 8-PSK is usually the highest order PSK constellation deployed."
http://en.wikipedia.org/wiki/Phase-shift_keying
Thank you very much !
Yes, your assumption is correct. In PSK or phase shift keying, the number indicates the number of different phase shifts that are used to represent binary patterns. In 8PSK, there are eight different phase shifts, and each phase shift represents one of the eight patterns of three bits. Likewise, in 256PSK, there are 256 different phase shifts, and each phase shift represents one of the 256 patterns of eight bits.
To confirm whether you are right, you can use the formula 2^n to calculate the total number of patterns for a given number of bits. In this case, n represents the number of bits. For example, 2^3 equals 8, which matches the number of patterns in 8PSK. Similarly, 2^8 equals 256, which matches the number of patterns in 256PSK.
So, based on the pattern of powers of 2, your assumption is correct.