What are the products of KOH + SO2?

I believe the product is K2SO3 but check me out on that. I know CaSO3 form from Ca(OH)2 and MgSO3 forms from Mg(OH)2.

Propane forms a flame and emits heat as it burns.

To determine the products of a chemical reaction, we need to consider the reactants and their chemical properties. In this case, we have the reactants potassium hydroxide (KOH) and sulfur dioxide (SO2).

To find the products, we need to understand the reactive behavior of these substances.

First, let's look at potassium hydroxide (KOH). It is an ionic compound composed of the potassium cation (K+) and the hydroxide anion (OH-). When KOH dissolves in water, it dissociates into its constituent ions:

KOH -> K+ + OH-

Next, let's consider sulfur dioxide (SO2). It is a molecular compound composed of one sulfur atom (S) bonded to two oxygen atoms (O). In an aqueous environment, SO2 can react with water to form sulfurous acid (H2SO3):

SO2 + H2O -> H2SO3

Now, when we combine KOH and SO2, we have:

KOH + SO2

Since both KOH and SO2 are soluble in water, we can expect them to form aqueous solutions.

The reaction between KOH and SO2 can result in the formation of potassium sulfite (K2SO3):

2 KOH + SO2 -> K2SO3 + H2O

During this reaction, the potassium cation (K+) from KOH combines with the sulfite anion (SO3^2-) derived from SO2 to produce potassium sulfite. Water (H2O) is also formed as a byproduct.

So, the products of the reaction between KOH and SO2 are potassium sulfite (K2SO3) and water (H2O).