Math(Please check)

Find the x coordinates of all relative extreme points of
f(x)=1/4x^4 + 2/3x^3- 3/2x^2 + 4

f'(x)=x^3 + 2x^2 - 3x = 0

(x^2 + 3)(x-1) = 0

x=-3 x=1 x=0 Is this correct?

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  1. I get when factoring

    x(x^2+2x-3)
    x(x+3)(x-1)=0
    x=0;-3, 1 same end as you, but your work is wrong.

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    bobpursley
  2. thank you

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