A 33kg traffic light hangs from a vertical beam by two wires. The wire on the left side of the light has an angle of 53 degrees to the beam and the right side wire has an angle of 37 degrees with the beam. Calculate the tension in each of the wires. Would the tension just be 33kg(sin53) + 33kg(cosin53) for the left side, and 33kg(sin37) + 33kg(cosine37) for the right side?

Call the left side tension T1 and the right side tension T2. Vertical and horizontal equilibrium equations are:

Mg = T1 cos53 + T2 cos37
0 = T1 sin53 - T2 sin37

Mg = T1 cos 53 + T1*cos37*(sin53/sin37)

T1 = Mg/(0.6918 + 1.0598)
= 0.5709 M*g

You set up the equations or did the algebra incorrectly, and you also omitted the g factor that you need to get the tension in Newtons.

Thanks , I knew this just didn't seem right.

To calculate the tension in each wire, you need to consider the forces acting on the traffic light. The two wires are supporting the weight of the traffic light, so their tensions will counteract the gravitational force.

For the left side wire, let's call the tension T1, and for the right side wire, let's call the tension T2.

To calculate T1, we need to decompose the weight of the traffic light into its components along the left wire. The vertical component is calculated as 33 kg * g * cos(53°), where g is the acceleration due to gravity (approximately 9.8 m/s²). This vertical force is balanced by T1. Therefore, we have:

T1 = 33 kg * g * cos(53°)

Similarly, for the right side wire, we need to decompose the weight into its components along the right wire. The vertical component is calculated as 33 kg * g * cos(37°). This vertical force is balanced by T2. Thus, we have:

T2 = 33 kg * g * cos(37°)

So, to calculate the tensions in each wire, you need to use the cosine of the angles and multiply it by the weight of the traffic light (33 kg) and the acceleration due to gravity (g ≈ 9.8 m/s²).

Therefore, the correct calculations for the tensions are:

T1 = 33 kg * 9.8 m/s² * cos(53°)
T2 = 33 kg * 9.8 m/s² * cos(37°)

Please note that the above calculations are based on assuming the wires are ideal and neglecting any other external forces.