an airplane is flying horizontally over ocean at the speed of 200 meters/seconds and at the altiude of 2000 meters.the pilot drops a flare.
A. how many second after release does the flare hit the water?
b.At what distance from point p,directly under point of release does the flare hit the water(what is the range of flare)?
Thanks for answering
Urgent? Is the flare going down?
height= vi*time-1/2 g t^2, here the downard velocity is zero initially, so figure time.
WEll again,
horizontal distance= vihorizontal*timeinair
yes mr.pursley
To determine how many seconds it takes for the flare to hit the water, we can use the equation of motion for free fall. The flare is only influenced by the force of gravity as it falls vertically downward while the airplane moves horizontally.
We know that the initial velocity of the flare in the vertical direction is 0 since it was dropped, and the acceleration due to gravity is approximately 9.8 m/s^2. The distance it falls vertically is 2000 meters.
We can employ the kinematic equation: d = v0 * t + (1/2) * a * t^2, where d represents the distance, v0 is the initial vertical velocity, a is the acceleration, and t is the time.
Plugging the values into the equation, we get:
2000 = 0 * t + (1/2) * 9.8 * t^2
2000 = 4.9 * t^2
t^2 = 2000/4.9
t ≈ 20.408 seconds (rounded to three decimal places)
Therefore, it takes approximately 20.408 seconds for the flare to hit the water.
To calculate the range of the flare, we can multiply the horizontal velocity of the airplane by the time it takes for the flare to hit the water.
Range = horizontal velocity * time
Range = 200 m/s * 20.408 s
Range ≈ 4081.6 meters (rounded to one decimal place)
Hence, the flare will hit the water after approximately 20.408 seconds and at a distance of approximately 4081.6 meters from the point directly beneath the release point.