Find Molecular and net ionic equation for
Al(NO3)3 + Na2CO3
see other post.
To find the molecular equation and net ionic equation for the reaction between aluminum nitrate (Al(NO3)3) and sodium carbonate (Na2CO3), we need to follow a few steps.
Step 1: Write the balanced molecular equation:
The balanced molecular equation can be written by combining the reactants' formulas, followed by balancing the equation based on the number of atoms present on each side:
Al(NO3)3 + 3Na2CO3 -> 3NaNO3 + Al2(CO3)3
Step 2: Identify the soluble and insoluble compounds:
In this reaction, all the compounds are soluble. However, it's important to note that aluminum carbonate (Al2(CO3)3) is a slightly soluble compound, meaning it will dissociate partially.
Step 3: Write the ionic equation:
Next, we can split all soluble compounds into their respective ions:
Al(NO3)3 (aq) + 3Na2CO3 (aq) -> 3NaNO3 (aq) + Al2(CO3)3 (s)
Step 4: Write the net ionic equation:
To obtain the net ionic equation, we need to remove the spectator ions - the ions that appear on both the reactant and product sides without undergoing any change. In this case, the spectator ions are sodium (Na+) and nitrate (NO3-) ions. We can remove those ions from the equation to get the net ionic equation:
Al3+ (aq) + 3CO3^2- (aq) -> Al2(CO3)3 (s)
Thus, the net ionic equation for the reaction between aluminum nitrate and sodium carbonate is:
Al3+ (aq) + 3CO3^2- (aq) -> Al2(CO3)3 (s)
To find the molecular and net ionic equations for the reaction between aluminum nitrate (Al(NO3)3) and sodium carbonate (Na2CO3), we need to first identify the chemical formulas of the products formed.
The balanced chemical equation for the reaction is as follows:
2 Al(NO3)3 + 3 Na2CO3 → Al2(CO3)3 + 6 NaNO3
Here, aluminum nitrate reacts with sodium carbonate to produce aluminum carbonate and sodium nitrate.
Now, let's break down the equation to find the molecular and net ionic equations:
Molecular Equation:
2 Al(NO3)3 + 3 Na2CO3 → Al2(CO3)3 + 6 NaNO3
Net Ionic Equation:
To find the net ionic equation, we need to eliminate the spectator ions - ions that appear on both sides of the equation unchanged. In this case, the spectator ions are the sodium ions (Na+) and the nitrate ions (NO3-).
2 Al3+ + 3 CO32- → Al2(CO3)3
This is the net ionic equation for the reaction between aluminum nitrate and sodium carbonate. It shows the ions that actually participated in the reaction, resulting in the formation of aluminum carbonate.