if Y = _X2 -6x - 8 find the value(s) of x when y =1.
x^2 - 6x - 8 = 1
x^2 - 6x - 9 = 0
Equation cannot be factored. Do you have typos?
if Y = X2(xsquared) -6x - 8 find the value(s) of x when y =1.
yes there was a typo its x squared i don't know how to rise the 2
Do as I do. x^2 = x squared.
x^2 - 6x - 8 = 1
x^2 - 6x - 9 = 0
This still cannot be factored.
(x-3)(x-3) = x^2 - 6x +9
(x-3)(x+3) = x^2 -9
To find the value(s) of x when y = 1 in the equation Y = _X^2 - 6x - 8, we can substitute Y with 1 and solve for x.
Substituting Y with 1, the equation becomes:
1 = _X^2 - 6x - 8
To solve this quadratic equation, we can rearrange it to the standard form:
_X^2 - 6x - 8 - 1 = 0
Simplifying further:
_X^2 - 6x - 9 = 0
Now, we can solve this quadratic equation using factoring, completing the square, or by applying the quadratic formula.
Let's solve it using the quadratic formula:
The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions for x are given by:
x = (-b ± √(b^2 - 4ac)) / (2a)
In our equation, a = 1, b = -6, and c = -9. Substituting these values into the quadratic formula:
x = (-(-6) ± √((-6)^2 - 4(1)(-9))) / (2(1))
Simplifying further:
x = (6 ± √(36 + 36)) / 2
x = (6 ± √(72)) / 2
x = (6 ± 6√2) / 2
Factoring out 2:
x = 3 ± 3√2
Therefore, the value(s) of x when y = 1 in the equation Y = _X^2 - 6x - 8 are x = 3 + 3√2 and x = 3 - 3√2.