If f(x)= sqrt(x+1) find f^-1 and sketch its graph.

If you can't sketch the graph that is fine I will figure that part out. Thanks

In google type:

functions graphs online

When you see list of results click on:

rechneronline.de/function-graphs/

When page be open in blue recatacangle type:

sqr(x+1)

If f^-1 mean 1/f(x) in grey rectacangle type:

1/sqr(x+1)

Then click option Draw

You will see graph of your functions.

Thank you very much

To find the inverse of a function, we usually start by swapping the x and y variables, and then solve for y. Let's do that for the given function f(x) = √(x+1):

1. Start with the equation: y = √(x+1)
2. Swap x and y: x = √(y+1)
3. Clear the square root by squaring both sides: x^2 = y + 1
4. Solve for y: y = x^2 - 1

Therefore, the inverse function f^(-1)(x) = x^2 - 1.

Now, to sketch the graph of the inverse function, you can follow these steps:

1. Start by plotting a few key points on the graph of the original function, f(x) = √(x+1).
- For example, you can choose x = 0, -1, 3, and 4, and calculate the corresponding y values using the original function.
- Plot these points on the coordinate plane.

2. Reflect the plotted points across the line y = x. This means swapping the x and y values for each point.
- For example, if a point on the graph of f(x) is (2, 3), then the corresponding point on the graph of f^(-1)(x) is (3, 2).

3. Connect the reflected points to form the graph of the inverse function, f^(-1)(x).

Keep in mind that the graph of the inverse function will be the reflection of the graph of the original function across the line y = x.