A 5.00x10^2-g block of metal absorbs 5016 J of heat when its temperature canges from 20.0 C to 30.0 C. Calculate the specific heat of the metal ..?
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To calculate the specific heat of the metal, you can use the formula:
Q = mcΔT
Where:
Q is the amount of heat absorbed (5016 J in this case)
m is the mass of the metal block (5.00x10^2 g)
c is the specific heat of the metal (unknown)
ΔT is the change in temperature (30.0°C - 20.0°C = 10.0°C)
We need to convert the mass of the metal block from grams to kilograms, because the SI unit for specific heat is J/(kg·°C):
Mass of the block (in kg) = 5.00x10^2 g ÷ 1000 g/kg = 0.500 kg
Now we can plug in the values into the formula and solve for c:
5016 J = 0.500 kg * c * 10.0°C
Divide both sides of the equation by (0.500 kg * 10.0°C):
c = (5016 J) / (0.500 kg * 10.0°C)
Calculating the value, we get:
c ≈ 1003.2 J/(kg·°C)
Therefore, the specific heat of the metal is approximately 1003.2 J/(kg·°C).
To calculate the specific heat of a substance, you can use the formula:
Q = mcΔT
Where:
Q is the amount of heat absorbed or released
m is the mass of the substance
c is the specific heat capacity
ΔT is the change in temperature
In this case, the mass of the metal is given as 5.00 x 10^2 g, the change in temperature (ΔT) is 30.0 °C - 20.0 °C = 10.0 °C, and the amount of heat absorbed (Q) is given as 5016 J.
To find the specific heat capacity (c), rearrange the formula to isolate c:
c = Q / (m * ΔT)
Now, substitute the given values into the equation:
c = 5016 J / (5.00 x 10^2 g * 10.0 °C)
Simplify the units:
c = 5016 J / (500 g * 10.0 °C)
c = 5016 J / 5000 g °C
c = 1.0032 J/g °C
Therefore, the specific heat of the metal is approximately 1.0032 J/g °C.