What chemical reaction is responsible for the endpoint observed when the NH3/NH4Cl buffer solution is titrated with HCl? Write a blanced ionic equation for the reaction.
NH3 + HCl ==> NH4Cl
So when HCl is added to an NH3/NH4Cl buffer, the NH4Cl (the salt...the acid) is increased and the NH3 (the base) is decreased. In effect, the HCl, a strong acid, is being replaced with a weak acid, NH4^+ and that is why buffers work so well.
Girl no one is ever right, sometimes you gotta listen to your gut if you have one and didn't get it removed because then I am so sorry for you anyways it should most likely be none because there more to the world then checking the pH of random solutions enjoy you life before the aliens attack YOLO
To determine the chemical reaction responsible for the observed endpoint when a NH3/NH4Cl buffer solution is titrated with HCl, we need to consider the components of the buffer solution.
The NH3/NH4Cl buffer solution consists of ammonia (NH3) and ammonium chloride (NH4Cl). In this buffer system, ammonia acts as a weak base, and ammonium chloride acts as its conjugate acid.
During the titration, when HCl (a strong acid) is added, it reacts with the weak base component of the buffer solution, ammonia (NH3), to form its conjugate acid, ammonium ion (NH4+). The reaction can be represented by the following balanced ionic equation:
NH3 + HCl -> NH4+ + Cl-
In this equation, one molecule of ammonia (NH3) reacts with one molecule of hydrochloric acid (HCl) to produce one ammonium ion (NH4+) and one chloride ion (Cl-).
The appearance of the endpoint indicates that all of the ammonia in the buffer solution has been neutralized by the added HCl, resulting in an excess of ammonium ions (NH4+).
Thus, the above chemical reaction is responsible for the observed endpoint when NH3/NH4Cl buffer solution is titrated with HCl.
If you prepare 1.2L of this NH4+/NH3 buffer using 0.56 mol NH3 and 1.0 mol of NH4+, what is the pH after adding a) 150mL of 1.0M HCl
I get the answer to be 8.8 for the pH. I set up a double ice table and found {OH} and then found pOH and pH. My friend got the answer to be 9.8. Who is right?