a bullet was fired at a target 50m away with a muzzle velocity of 300m/s. if the barrel of the gun was horizontal, how far below the level of the gun did the bullet strike th target?

Question

a bullet was fired at a target 50m away with a muzzle velocity of 300m/s. if the barrel of the gun was horizontal, how far below the level of the gun did the bullet strike th target?

Answer 1

if the maximum safe breaking acceleration of a navy fighter is 15m/s^2 and an aircraft carrier's deck is 100m long, with what maximum speed can a fighter safely land on the deck and still stop completely on the ship?

Answer 2

To find the vertical distance below the level of the gun where the bullet strikes the target, we need to analyze the projectile motion of the bullet. We can split the motion into horizontal and vertical components.

First, let's consider the horizontal component. Since the barrel of the gun was horizontal, there will be no change in the horizontal motion of the bullet. Therefore, the horizontal distance traveled by the bullet will be the same as the distance to the target, which is 50 m.

Now, let's focus on the vertical component. We need to determine the time it takes for the bullet to reach the target. We can use the equation:

distance = velocity × time + (1/2) × acceleration × time^2

In the vertical direction, the initial velocity is 0 m/s (since there is no initial upward or downward velocity), the distance is the vertical distance below the level of the gun where the bullet strikes the target (we'll call it 'd'), and the acceleration is due to gravity, which is approximately 9.8 m/s^2 (assuming no air resistance). Thus, the equation becomes:

d = (1/2) × 9.8 m/s^2 × time^2

Since the time it takes for the bullet to reach the target is the same for both the horizontal and vertical components, we can use the horizontal distance (50 m) and the muzzle velocity (300 m/s) to find the time. We'll use the equation:

distance = velocity × time

For the horizontal component:
50 m = 300 m/s × time
(time = 50 m / 300 m/s)
time = 0.167 seconds

Now, we can substitute this value of time into the equation for the vertical component:

d = (1/2) × 9.8 m/s^2 × (0.167 seconds)^2

Calculating this expression, we find:

d ≈ 0.262 meters

Therefore, the bullet strikes the target approximately 0.262 meters (or 26.2 cm) below the level of the gun.

a bullet was fired at a target 50m away with a muzzle velocity of 300m/s. if the barrel of the gun was horizontal, how far below the level of the gun did the bullet strike th target?

if the maximum safe breaking acceleration of a navy fighter is 15m/s^2 and an aircraft carrier's deck is 100m long, with what maximum speed can a fighter safely land on the deck and still stop completely on the ship?

V1=10m/s

To find the vertical distance below the level of the gun where the bullet strikes the target, we need to analyze the projectile motion of the bullet. We can split the motion into horizontal and vertical components.