can anyone help me one this
4x(x-4)-5x(x-3)=0
solve for x
Given
4x(x-4)-5x(x-3)=0
since there is a common factor x, we can extract the common factor to make the solution easier:
x[4(x-4)-5(x-3)]=0
Now expand the expression inside of the square brackets:
x[4x-16-5x+15]=0
Simplify:
x[-x-1]=0
-x[x+1]=0
We can get a zero if and only if each of the factors on the left hand side equals zero, which means
x=0, or x+1=0
So the solution of the equation is
x=0, or x=-1.