The amount of heat released when 100 grams of steam at 100 degrees Celsius
is converted into liquid water at 100 degrees Celsius is ____ J.
To calculate the amount of heat released when steam is converted into liquid water, we need to use the concept of specific heat and heat of vaporization.
First, let's break down the process into two steps:
1. Cooling the steam from its initial temperature to 100 degrees Celsius, where it turns into water (condensation).
2. Cooling the water from 100 degrees Celsius to its final temperature, which is also 100 degrees Celsius.
Step 1: Cooling the steam to 100 degrees Celsius
To calculate the heat released during this step, we need to determine the amount of heat required to cool the steam from its initial temperature to the boiling point, which is 100 degrees Celsius. This can be done using the formula:
Q1 = m * c1 * ΔT1
Where:
Q1 is the heat released,
m is the mass of the steam (given as 100 grams),
c1 is the specific heat capacity of steam (calculated using tables or given values),
ΔT1 is the temperature change (initial temperature - boiling point).
Step 2: Cooling the water from 100 degrees Celsius to 100 degrees Celsius
Although this step seems unnecessary, we still need to account for the specific heat of water. The formula to calculate the heat released during this step is:
Q2 = m * c2 * ΔT2
Where:
Q2 is the heat released,
m is the mass of the water (also given as 100 grams),
c2 is the specific heat capacity of water (given as a constant),
ΔT2 is the temperature change (initial temperature - final temperature).
Finally, to determine the total amount of heat released, we add Q1 and Q2:
Total Heat Released = Q1 + Q2
Remember to substitute the appropriate values into the equations and convert units if necessary.