can the quadratic equation be used on -3p^2+66p+9
Yes, the quadratic formula can be used on any equation with the format ax^2 + bx + c.
how would I go about doing it and would it give me the answer for p?
Yes, the quadratic formula is a way of solving for x (or p in this case).
The Quadratic Formula states that for any equation ax^2 + bx + c...
x = -b +- √(b^2 - 4ac) all over 2a.
Identify your a, b, and c, and then plug and chug.
I got -22.13552873 and -.1355287257...is this right? It does not make any sense though because this should be a price charged to obtain the largest revenue
Your 22... should be positive. Check your work for a sign error.
The +- means plus or minus. (You'll always have two answers.)
Yes, the quadratic equation can be used to solve the equation -3p^2 + 66p + 9 = 0.
The quadratic equation is given by:
p = (-b ± √(b^2 - 4ac)) / (2a)
For the equation -3p^2 + 66p + 9 = 0, the coefficients in the quadratic equation are:
a = -3
b = 66
c = 9
Substituting these values into the quadratic equation, we get:
p = (-(66) ± √((66)^2 - 4(-3)(9))) / (2(-3))
Simplifying further:
p = (-66 ± √(4356 + 108)) / (-6)
p = (-66 ± √(4464)) / (-6)
Now, you can calculate the two possible solutions for p by evaluating both the plus and minus signs:
p₁ = (-66 + √(4464)) / (-6)
p₂ = (-66 - √(4464)) / (-6)
Calculating these values will give you the solutions for p in the equation -3p^2 + 66p + 9 = 0.