# algebra investments

Peter invested some money at 6% annual interest and martha invested some at 12%. If their investments is \$6000 and their combined interest was \$540. How much money did martha invest?

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1. Let Peter's investment be x
then Martha's investment is 6000-x

solve:

.06x + .12(6000-x) = 540
6x + 12x(6000-x) = 54000

I am sure you can finish it.

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2. 4000

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3. 3000

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