algebra investments

Peter invested some money at 6% annual interest and martha invested some at 12%. If their investments is $6000 and their combined interest was $540. How much money did martha invest?

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  1. Let Peter's investment be x
    then Martha's investment is 6000-x

    solve:

    .06x + .12(6000-x) = 540
    6x + 12x(6000-x) = 54000

    I am sure you can finish it.

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  2. 4000

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  3. 3000

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