how do you fill in the table for y=1/2 (x-8)

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  1. If you're referring to an x-y table then would you not just sub in a value for x and find the consequent value for y?

    For example:

    Lets sub in 0 for x
    y= 1/2 (0-8)
    y = 1/2 (-8)
    y = -4

    Lets sub in 1 for x
    y= 1/2 (1-8)
    y = 1/2 (-7)
    y = -3.5

    I believe this is what you're asking. You would simply do so for as many values as you'd like. I started at 0 but you could certainly go into negative x-values such as -1 or -2.

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