Hello, i seem to be stuck on a problem and do'nt know why im not gettin the right answer.I have the he Ka and Kb values for each of the weak acids and bases from the chart and I keep getting zero and the second one 2.27*10^-24 is this correct?? Thank uu

Solve an equilibrium problem (using an ICE table) to calculate the of each of the following. a solution that is 0.175M in HC2H3O2 and 0.120M in KC2H3O2.

as well as a solution that is 0.195M in CH3NH2 and 0.110 CH3NH3BR in

To solve this problem, you need to set up an ICE table and use the given concentrations to calculate the equilibrium concentrations. Here's how you can approach each part of the problem:

For the solution of HC2H3O2 and KC2H3O2:
Step 1: Write the balanced chemical equation for the reaction between HC2H3O2 and KC2H3O2:

HC2H3O2(aq) + H2O(l) ⇌ H3O+(aq) + C2H3O2-(aq)

Step 2: Set up the ICE table for the reaction:

HC2H3O2 + H2O ⇌ H3O+ + C2H3O2-
I 0.175 - - -
C -x - x x
E ? - ? ?

Step 3: Identify the initial concentrations and calculate the equilibrium concentrations using the ICE table. Since the reaction involves a weak acid and its conjugate base, you can use the Ka value for HC2H3O2. Let's assume that the value of Ka is provided.

Using the given concentration of HC2H3O2, you have [HC2H3O2] = 0.175 M. Since HC2H3O2 dissociates to form H3O+ and C2H3O2-, the initial concentration of H3O+ and C2H3O2- is zero. Therefore, at equilibrium, the concentration of H3O+ is x, and the concentration of C2H3O2- is also x.

Step 4: Use the Ka value to set up an expression for the equilibrium constant:

Ka = [H3O+][C2H3O2-] / [HC2H3O2]

Step 5: Substitute the equilibrium concentrations into the expression and solve for x:

Ka = x^2 / (0.175 - x)

Step 6: Since the value of Ka should be known, you can solve the equation for x using algebraic methods.

Repeat the above steps for the second equation involving CH3NH2 and CH3NH3BR, using the Kb value for CH3NH2.

By following these steps, you should be able to calculate the equilibrium concentration of each species in the given solutions. Please note that the specific values of Ka and Kb cannot be determined without the actual values provided in the problem statement.