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A group of 50,000 randomly selected adults were survey about whether they drink at least 6 8-oz glasses of water each day. Only 35% said yes to the question.
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Looking for someone to verify my homework answers on identifying the sample and population......
1) A group of 50,000 randomly
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You are correct. In 2, you are only drawing from the population of the LOCAL emporium's customers.
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In a survey, 39% of a randomly selected sample of n = 935 American adults said that they do not get enough sleep each night. The
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To create a 95% confidence interval for the percentage of American adults who feel they don't get
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In a survey, 39% of a randomly selected sample of n = 935 American adults said that they do not get enough sleep each night. The
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To create a 95% confidence interval for the percentage of American adults who feel they don't get
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The table shows the drink preferences of 50 shoppers at the mall. What is the probability that one shopper, selected at random
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The probability that a shopper preferred either Drink B or Drink A is the sum of the probabilities
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1. A group of researchers want to investigate if a newly designed word puzzle game has a positive eect on
improving the memory of
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The flaw in the design of this experiment is that the participants are not randomly placed in either
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1. A group of researchers want to investigate if a newly designed word puzzle game has a positive eect on
improving the memory of
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The flaw in the design of this experiment is that the participants are selecting which group they
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.8 probability that a randomly selected adult will watch prime time tv live, instead of online, on DVR, etc.. Assume that seven
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prob(watch live) = .8 prob(not live) = .2 fewer than three of 7 means: 0 live, 1 live, or 2 live
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In a large survey, it was discovered that 1 out of every 5 adults visits Disney World every year. If 30 adults are randomly
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To find the probability, we need to use the binomial probability formula. The formula is given by:
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in a large survey, it was discovered that 1 out of every 5 adults visits disney world every year. if 30 adults are randomly
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prob of visit = 1/5 = p = .2 Binomial dist: p(x = 7) = [30:7] .2^7 (.8)^23 look up binomial coef
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A group of adults of 200 aged 21 to 50 were selected from those entering Fit Right Health stores in Washington state, and were
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The population is the group of random people selected that entered Fit Right Health. The samples are
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