A tree casts a 25 foot shadow. At the same time of day, a 6 foot man standing near the tree casts a 9 foot shadow. What is the approximate height of the tree to the nearest foot?
Don't you understand the solution I posted for you?
http://www.jiskha.com/display.cgi?id=1301010240
obviously not
your suppose to use Pythagorean Theorem
(a2+b2=c2
In the diagram, a building casts a 35-ft shadow and a flagpole casts an 8-ft shadow. If the flagpole is 18 ft tall, how tall is the building? Round to the nearest tenth.
The angle of depression from the top of the tree to the tip of the shadow is 25°. Find the height of the tree to the nearest tenth.
To determine the approximate height of the tree, we can use the concept of similar triangles.
First, let's identify the two triangles involved in this problem. Triangle 1 represents the tree and its shadow, while Triangle 2 represents the man and his shadow.
Let's label the height of the tree as 'h' and the length of its shadow as 's'. Similarly, let's label the height of the man as 'm' and the length of his shadow as 't'.
Now, we can set up a proportion using the corresponding sides of the triangles:
h / s = m / t
Substituting the given values, we get:
h / 25 = 6 / 9
To solve for 'h', we can cross-multiply and then divide:
h * 9 = 6 * 25
h * 9 = 150
h = 150 / 9
h ≈ 16.67 (rounded to two decimal places)
Therefore, the approximate height of the tree is 17 feet (rounded to the nearest foot).