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In a circle whose radius is 6, find the area of a sector, in terms of pi, whose center angle contains 30 degrees
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A sector of a circle with radius r cm contains an angle of θ radians between the bounding radii. Given that the perimeter of
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please check my answers.
1.Find the area of the sector of a circle. r=11.8cm, theta-pi/7 radians I got 31.2cmsquared 2.Find the
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1. 31.24 yes 2.17.04 yes 3. total area = pi r^2 = pi(64) angle/2pi =45/64 pi angle = 45/32 = 1.41
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The area of a sector of a circle is given by the formula A = (θ/360)πr^2, where θ is the central
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In a circle whose radius is 6, find the area of a sector, in terms of pi, whose center angle contains 30 degrees
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As = ((pi/6)/2pi)*pi *6^2 As = 1/6 * 1/2 * 36pi = 3pi.
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ABC is a sector of a circle with
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a circle of radius, r, with a sector of 45° shaded.
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To find the area of a sector, you can use the formula: Area of a sector = (θ/360) * π * r^2 where
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A sector of a circle radius 6cm subtend an angle of 105° at the center of the circle calculate
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To find the perimeter of the sector, we need to know the length of the arc. The length of an arc can
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