If you have 1.8 moles of magnesium and 3.2 moles of chlorine, what is the product of the reaction. what is the limiting regent? what is the Theoretical yield in grams and moles? show work?
Mg + Cl2 -> MgCl
limiting reagent= the reactant that produces the lesser amount of product
http://www.chem.tamu.edu/class/majors/tutorialnotefiles/limiting.htm
theoretical yield (see d)
http://chemistry.about.com/od/workedchemistryproblems/a/limiting-reactant-theoretical-yield.htm
To determine the product of the reaction, the limiting reagent, and the theoretical yield, we need to balance the equation and compare the mole ratios.
The balanced chemical equation for the reaction between magnesium (Mg) and chlorine (Cl₂) is:
Mg + Cl₂ → MgCl₂
Now, let's determine the limiting reagent. The limiting reagent is the reactant that is completely consumed in the reaction, thus limiting the amount of product that can be formed.
Step 1: Calculate the moles of the reactants:
Moles of magnesium (Mg) = 1.8 moles
Moles of chlorine (Cl₂) = 3.2 moles
Step 2: Determine the stoichiometric ratio:
From the balanced equation, we can see that 1 mole of Mg reacts with 1 mole of Cl₂ to produce 1 mole of MgCl₂.
Step 3: Compare the moles of reactants with the stoichiometric ratio:
In this case, 1 mole of Mg reacts with 1 mole of Cl₂. Both reactants have a 1:1 mole ratio.
Step 4: Determine the limiting reagent:
Since both reactants have the same mole ratio, the reactant with a lower number of moles will be the limiting reagent. In this case, magnesium has 1.8 moles, while chlorine has 3.2 moles. Therefore, magnesium is the limiting reagent.
Step 5: Calculate the theoretical yield:
Since magnesium is the limiting reagent, the amount of magnesium chloride (MgCl₂) formed will depend on the moles of magnesium.
Moles of MgCl₂ = Moles of Mg
Therefore, the theoretical yield of MgCl₂ in moles is 1.8 moles.
To convert the moles of MgCl₂ to grams, we need to know the molar mass of MgCl₂. The molar mass of magnesium chloride is 95.21 g/mol.
Step 6: Calculate the theoretical yield in grams:
Theoretical yield (in grams) = Moles of MgCl₂ × Molar mass of MgCl₂
Theoretical yield (in grams) = 1.8 moles × 95.21 g/mol
Calculate the value to find the theoretical yield in grams.
Please note that the above calculation assumes the reaction goes to completion without any side reactions or losses during the process.