Give the molecular, complete ionic, and net ionic equations for the reaction of barium nitrate and sodium sulfate.
Sure! Let's break it down step by step:
Step 1: Write the balanced molecular equation:
Ba(NO3)2 + Na2SO4 -> BaSO4 + 2NaNO3
Step 2: Write the balanced complete ionic equation:
Ba^2+ + 2NO3^- + 2Na^+ + SO4^2- -> BaSO4 + 2Na^+ + 2NO3^-
Step 3: Write the balanced net ionic equation:
Ba^2+ + SO4^2- -> BaSO4
So, the molecular equation is Ba(NO3)2 + Na2SO4 -> BaSO4 + 2NaNO3,
the complete ionic equation is Ba^2+ + 2NO3^- + 2Na^+ + SO4^2- -> BaSO4 + 2Na^+ + 2NO3^-, and
the net ionic equation is Ba^2+ + SO4^2- -> BaSO4.
To determine the molecular equation, complete ionic equation, and net ionic equation for the reaction between barium nitrate (Ba(NO3)2) and sodium sulfate (Na2SO4), we need to understand the solubility rules and the nature of the compounds involved.
1. Write the molecular equation:
Barium nitrate (Ba(NO3)2) dissociates into Ba2+ and 2NO3- ions.
Sodium sulfate (Na2SO4) dissociates into 2Na+ and SO42- ions.
So, the molecular equation is:
Ba(NO3)2 + Na2SO4 → BaSO4 + 2NaNO3
2. Write the complete ionic equation:
In the complete ionic equation, we write all the soluble ionic compounds as separate ions.
Ba2+(aq) + 2NO3-(aq) + 2Na+(aq) + SO42-(aq) → BaSO4(s) + 2Na+(aq) + 2NO3-(aq)
3. Write the net ionic equation:
In the net ionic equation, we remove the spectator ions; these are the ions that appear on both sides of the equation and do not participate in the reaction.
The spectator ions are 2Na+ and 2NO3-.
The net ionic equation for the reaction is:
Ba2+(aq) + SO42-(aq) → BaSO4(s)
So, the molecular equation is Ba(NO3)2 + Na2SO4 → BaSO4 + 2NaNO3, the complete ionic equation is Ba2+(aq) + 2NO3-(aq) + 2Na+(aq) + SO42-(aq) → BaSO4(s) + 2Na+(aq) + 2NO3-(aq), and the net ionic equation is Ba2+(aq) + SO42-(aq) → BaSO4(s).