How many atoms of each element are present in five formula units of calcium permanganate?
To determine the number of atoms of each element present in five formula units of calcium permanganate, we need to know the chemical formula of calcium permanganate. Calcium permanganate's formula is Ca(MnO4)2.
Let's break down the formula and count the atoms of each element individually.
1. Calcium (Ca): Each formula unit of calcium permanganate contains one calcium atom, as indicated by the 'Ca' in the formula.
2. Manganese (Mn): Each permanganate ion (MnO4-) contains one manganese atom. In calcium permanganate, there are two permanganate ions, so there are two manganese atoms.
3. Oxygen (O): Each permanganate ion (MnO4-) contains four oxygen atoms. Since there are two permanganate ions in calcium permanganate, there are a total of eight oxygen atoms.
Now that we have counted the atoms individually, let's calculate the number of atoms in five formula units of calcium permanganate:
1. Calcium (Ca): 1 calcium atom * 5 formula units = 5 calcium atoms
2. Manganese (Mn): 2 manganese atoms * 5 formula units = 10 manganese atoms
3. Oxygen (O): 8 oxygen atoms * 5 formula units = 40 oxygen atoms
Therefore, in five formula units of calcium permanganate, there are 5 calcium atoms, 10 manganese atoms, and 40 oxygen atoms.