A cannon of mass 200kg, fires a cannonball with a mass of 10kg. The cannon ball leaves the barrel of the cannon with a velocity of 60 m/s. Using the law of conservation of momentum , explain what happens to the cannon when the cannon ball is fired. (Answer should include calculation.)

Well, I guess this cannon is fired horizontally.

final momentum = 200 v + 10 *60 = initial momentum = 0
so
v = - 600/200 = -3 m/s

Why is it 200v ??Is the formula used :

m1v2+m2v2=(m1+m2)v ???

Confusedd

Pbefore = Pafter

(m1v2)+(m2v2) = (m1v2)+(m2v2)

To explain what happens to the cannon when the cannonball is fired, we can use the law of conservation of momentum. According to this law, the total momentum before an event is equal to the total momentum after the event, as long as no external forces are acting on the system.

In this case, we have a cannon of mass 200 kg and a cannonball of mass 10 kg. The cannonball leaves the barrel of the cannon with a velocity of 60 m/s.

To find the initial momentum of the cannonball, we can use the equation:

Initial momentum of cannonball = mass of cannonball * velocity of cannonball

Plugging in the values, we get:

Initial momentum of cannonball = 10 kg * 60 m/s
Initial momentum of cannonball = 600 kg*m/s

Now, to find the final momentum of the system, we need to consider the momentum of the cannon and the cannonball combined. Since the cannonball is the only object that has a velocity after the event, the final momentum of the system will be the same as the initial momentum of the cannonball.

Final momentum of the system = Initial momentum of cannonball
Final momentum of the system = 600 kg*m/s

Since the total momentum of the system is conserved, the cannon's momentum must be equal in magnitude but opposite in direction to the cannonball's momentum. Therefore, the final momentum of the cannon is:

Final momentum of cannon = -600 kg*m/s

According to the law of conservation of momentum, the cannon gains momentum equal in magnitude but opposite in direction to the cannonball's momentum. This means that the cannon recoils in the opposite direction with a momentum of -600 kg*m/s.

So, when the cannonball is fired, the cannon recoils backward with a momentum of -600 kg*m/s.