How many grams of water are present in 0.500 moles of calcium sulfate hemihydrate?
CaSO4.(1/2)H2O
0.5 mole = how many grams. (g = moles x molar mass)
What percentage water is in CaSO4.(1/2)H2O
To find the number of grams of water present in 0.500 moles of calcium sulfate hemihydrate, we first need to determine the molar mass of water.
The molar mass of water (H2O) can be calculated by summing the atomic masses of its constituent elements: hydrogen (H) and oxygen (O). The atomic masses of hydrogen and oxygen are approximately 1.01 g/mol and 16.00 g/mol, respectively.
So, the molar mass of water (H2O) is:
(2 * atomic mass of hydrogen) + atomic mass of oxygen = (2 * 1.01 g/mol) + 16.00 g/mol = 18.02 g/mol.
Now, we can calculate the mass of water by multiplying the molar mass of water by the number of moles:
Mass of water = Molar mass of water * Number of moles
= 18.02 g/mol * 0.500 mol
= 9.01 grams of water are present in 0.500 moles of calcium sulfate hemihydrate.