THREE PAINTINGS ARE SHAPED LIKE AN 8 FOOT SQUARE A 7 FOOT BY 4 FOOT RECTANGLE AND A TRIANGLE AND A TRIANGLE WITH A 6 FOOT BASE AND A HEIGHT OF 7 FEET IF THOSE PAINTING ARE HUNG TOGETHER ON THE OUTSIDE OF THE BUILDING, HOW MUCH OF THE BUILDING WALL WILL THEY COVER ALL TOGETHER?
Find the areas of each of these paintings.
http://www.mathsisfun.com/area.html
Then, add these areas together.
To find out how much of the building wall the paintings will cover altogether, we first need to calculate the total area of each painting.
1. Square Painting:
The square painting has a side length of 8 feet, so the area can be calculated by multiplying the side length by itself: 8 feet * 8 feet = 64 square feet.
2. Rectangle Painting:
The rectangle painting has dimensions of 7 feet by 4 feet, so the area can be found by multiplying the length by the width: 7 feet * 4 feet = 28 square feet.
3. Triangle Painting:
The triangle painting has a base of 6 feet and a height of 7 feet. To calculate the area of a triangle, you can use the formula: Area = (base * height) / 2. Plugging in the values: (6 feet * 7 feet) / 2 = 21 square feet.
Now that we know the area of each painting, we can add them together to find the total area they will cover on the building wall:
64 square feet (square painting) + 28 square feet (rectangle painting) + 21 square feet (triangle painting) = 113 square feet.
Therefore, the three paintings will cover a total of 113 square feet on the building wall.