What volume would be occupied by 100 g of oxygen gas at a pressure of 1.50 atm and a temp of 25 degrees C.
Use PV = nRT. Don't forget T must be in kelvin.
To find the volume of a gas, we can use the ideal gas law, which is given by the equation:
PV = nRT
where:
P = pressure (in atm),
V = volume (in liters),
n = number of moles of gas,
R = ideal gas constant (0.0821 L·atm/(mol·K)),
T = temperature (in Kelvin).
In order to use this equation, we need to convert the given values to the appropriate units.
First, let's convert the temperature from degrees Celsius to Kelvin. To do this, we add 273.15 to the given temperature:
T = 25°C + 273.15 = 298.15 K
Next, we need to convert the mass of the gas (in grams) to moles. To do this, we use the molar mass of oxygen, which is approximately 32 g/mol.
n = mass / molar mass
n = 100 g / 32 g/mol ≈ 3.125 mol
Now we have all the values we need to solve for the volume:
PV = nRT
V = (nRT) / P
Substituting the values:
V = (3.125 mol * 0.0821 L·atm/(mol·K) * 298.15 K) / 1.50 atm
V ≈ 16.37 liters
Therefore, 100 g of oxygen gas at a pressure of 1.50 atm and a temperature of 25 degrees C would occupy approximately 16.37 liters.
To determine the volume of a gas at a given pressure and temperature, we can use the ideal gas law equation:
PV = nRT,
where:
P = pressure (in atm),
V = volume (in liters),
n = number of moles of gas,
R = ideal gas constant (0.0821 L atm/mol K), and
T = temperature (in Kelvin).
First, we need to convert the given temperature from Celsius to Kelvin by adding 273.15:
Temperature in Kelvin = 25 degrees C + 273.15 = 298.15 K.
Next, we need to determine the number of moles of oxygen gas. To do this, we can use the molar mass of oxygen, which is approximately 32 g/mol. We can set up a conversion:
100 g O2 * (1 mol O2 / 32 g O2) = 3.125 mol O2.
Now, we have all the values we need to solve for the volume. Rearranging the ideal gas law equation, we get:
V = (nRT) / P.
Plugging in the values:
V = (3.125 mol * 0.0821 L atm/mol K * 298.15 K) / 1.50 atm.
V ≈ 49.66 liters.
Therefore, 100 g of oxygen gas at a pressure of 1.50 atm and a temperature of 25 degrees C would occupy approximately 49.66 liters of volume.