Questions LLC
Login
or
Sign Up
Ask a New Question
Math
Calculus
Find the inflection point(s), if any, of the function.
g(x)= 4x(^3)-4x
1 answer
They are the places where the second derivative is zero.
You can
ask a new question
or
answer this question
.
Similar Questions
Find all relative extrema and points of inflection of the function:
f(x) = sin (x/2) 0 =< x =< 4pi =< is supposed to be less than
Top answer:
To find the relative extrema of the function, we need to find the points where the derivative is
Read more.
If f(x) is a continuous function with f"(x)=-5x^2(2x-1)^2(3x+1)^3 , find the set of values for x for which f(x) has an
Top answer:
clearly, f"=0 at {0,1/2,-1/3} However, for an inflection point, f' must not change sign. (Think of
Read more.
Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x) = 3x(1/3) + 6x(4/3). You must
Top answer:
I assume you mean y = 3x^(1/3) + 6x^(4/3) = 3(2x+1) x^(1/3) y' = x^(-2/3) + 8x^(1/3) = (8x+1)
Read more.
one more question!!
what values of c deos the polynomial f(x) = x^4 + cx^3 + x^2 have two inflection points? one inflection
Top answer:
I'm sorry, but "BOZOOOOOOOOOOOOOOOOOOOOOOOOOO" is not a recognizable term or question. Is there
Read more.
Question – 1: The gradient of the graph of f(x) at any point is,ax^2-12x + 9, and the point,(2,-3),is an inflection point of
Top answer:
1. Integrate the gradient function ax^2-12x + 9 to get f(x), except for an arbitary constant C. f(x)
Read more.
Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x)=9x^1/3+9/2x^4/3.
I've gotten -0.5 as
Top answer:
Your lack of brackets leave the interpretation of the equation very ambiguous. e.g. do you mean:
Read more.
find the inflection points of the function: f9x)=x^2(ln(x))
Now I don't think there are any inflection points because both
Top answer:
correct.
Read more.
Find all relative extrema and points of inflection for the following function...
h(X)= X^2+5X+4/ X-1 min= max= inflection points=
Top answer:
I will assume you meant: h(x) = x^2 + 5x + 4/(x-1) h ' (x) = 2x + 5 - 4/(x-1)^2 = 0 for max/min 2x +
Read more.
The function g(x) is a dilation of f(x).
The graph of cube root function F of X has an inflection point at (negative 5, 0). The
Top answer:
D) b=1/3
Read more.
Consider the function f(x)=x^3+ax^2+bx+c that has a relative minimum at x=3 and an inflection point at x=2.
a). Determine the
Top answer:
f' = 3x^2 + 2ax + b f" = 6x+2a You know that f"(2) = 0 12+2a = 0 a = -6 Now do the same with f'(3)=0
Read more.
Related Questions
2. Consider the function f defined by f(x)=(e^X)cosx with domain[0,2pie] .
a. Find the absolute maximum and minimum values of
3. Given the function defined by y = x + sinx for all x such that -π/2<=x<=3π/2
a. Find the coordinate of all maximum and
Let f be the function defined by f(x)=xe^(1-x) for all real numbers x.:
a. Find each interval on which f is increasing. b. Find
The graph of y = x cubed is transformed as shown in the graph below. Which equation represents the transformed function?
On a
The graph of the function y=x^5-x^2+sinx has a point of inflection at x=
a. 0.324 b. 0.499 c. 0.506 d. 0.611 e. 0.704 Thanks.
let f be the function
f(x) = x^3 + 3x^2 - x + 2 a. the tangent to the graph of f at the point P = (-2,8) intersects the graph of
Explain why or why not:
1. if f'(c)=0, then f has a local maximum or minimum at c. 2. if f''(c)=0, then f has an inflection point
Consider the function f(x)=x^n e^(-2x) for x >/= 0, n > 2
A. Find the constant n for which the function f(x) attains its maximum
#1. A cubic polynomial function f is defined by f(x) = 4x^3 +ax^2 + bx + k
where a, b and k are constants. The function f has a
Consider the following function.
f(x) = (6 − x)e^−x (c) Find the point of inflection. (If an answer does not exist, enter
