College Physics II

An electric field of 2.04 kV/m and a magnetic field of 0.548 T act on a moving electron to produce no net force. If the fields are perpendicular to each other, what is the electron's speed?

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  1. Require that the magnetic and electrical forces be equal.

    e*V*B = e*E

    The charge, e, cancels out, so

    V = (E/B)

    If E is in V/m (NOT kV/m), and B is in Tesla, the answer will be in m/s.

    V = 2040/0.548 = ?

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