In a performance test, each of two cars takes 9.4 s to accelerate from rest to 24 m/s. Car A has a mass of 1358 kg, and car B has a mass of 2014 kg. Find the net average force that acts on (a) car A and (b) car B during the test.

(Average force)*time = (Momentum change) = (Mass)*(Velocity)

For car A, Fav = 1358*24/9.4 = __ N

Use the same formula for car B, but with the different mass.

To find the net average force that acts on each car during the test, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.

Let's start with car A:
- Car A has a mass of 1358 kg.
- The final velocity of car A is 24 m/s, and it starts from rest (0 m/s).
- The time taken by car A to accelerate from rest to 24 m/s is 9.4 s.

To find the acceleration of car A, we can use the equation:
acceleration = (final velocity - initial velocity) / time
Acceleration of car A = (24 m/s - 0 m/s) / 9.4 s
= 2.553 m/s²

Now, we can calculate the net average force acting on car A using Newton's second law:
Force on car A = mass of car A * acceleration of car A
Force on car A = 1358 kg * 2.553 m/s²
= 3469.274 N

Hence, the net average force acting on car A during the test is approximately 3469.274 Newtons.

Similarly, we can calculate the net average force acting on car B:
- Car B has a mass of 2014 kg.
- The final velocity of car B is also 24 m/s.
- The time taken by car B to accelerate from rest to 24 m/s is 9.4 s.

Using the same steps as above, we find:
Acceleration of car B = (24 m/s - 0 m/s) / 9.4 s
= 2.553 m/s²

Force on car B = 2014 kg * 2.553 m/s²
= 5143.402 N

Therefore, the net average force acting on car B during the test is approximately 5143.402 Newtons.