how many ml of 6m hcl aq are required to react with .10g of mg?
Just follow the steps.
http://www.jiskha.com/science/chemistry/stoichiometry.html
To determine the amount of 6M HCl (hydrochloric acid) solution needed to react with 0.10g of Mg (magnesium), you can follow these steps:
Step 1: Write out and balance the chemical equation for the reaction between HCl and Mg:
Mg + 2HCl → MgCl2 + H2
Step 2: Calculate the number of moles of Mg. You can use the molar mass of magnesium (24.31 g/mol) to convert grams to moles:
moles of Mg = mass / molar mass
moles of Mg = 0.10g / 24.31 g/mol
Step 3: Determine the stoichiometry of the reaction. From the balanced equation, we see that it takes 2 moles of HCl to react with 1 mole of Mg.
Step 4: Calculate the number of moles of HCl needed using the mole ratio from the stoichiometry:
moles of HCl = 2 * moles of Mg
Step 5: Calculate the volume of HCl solution using the concentration (6M) and the number of moles of HCl:
volume of HCl (in liters) = moles of HCl / concentration
Step 6: Convert the volume of HCl from liters to milliliters:
volume of HCl (in milliliters) = volume of HCl (in liters) * 1000 mL
Now you can plug in the values and calculate the result.
Please note that it is important to wear proper protective equipment and handle chemicals safely when performing experiments or working with strong acids like HCl.
To determine the volume of 6M HCl solution required to react with 0.10g of Mg, we need to follow these steps:
Step 1: Write and balance the chemical equation:
Mg + 2HCl -> MgCl2 + H2
Step 2: Calculate the number of moles of Mg:
moles = mass / molar mass
where the molar mass of Mg is 24.31 g/mol.
moles = 0.10g / 24.31 g/mol ≈ 0.0041 mol
Step 3: Use stoichiometry to find the molar ratio between Mg and HCl:
From the balanced equation, we know that 1 mol of Mg reacts with 2 moles of HCl.
Step 4: Convert moles of Mg to moles of HCl:
moles of HCl = moles of Mg × (2 moles of HCl / 1 mole of Mg) = 0.0041 mol × 2 ≈ 0.0082 mol
Step 5: Calculate the volume of HCl solution using its molarity:
Molarity (M) = moles / volume (in liters)
Rearrange the equation:
volume (in liters) = moles / Molarity
Convert 6M (6 moles per liter) to moles per milliliter by dividing by 1000:
volume (in milliliters) = moles / (Molarity × 1000)
volume (in milliliters) = 0.0082 mol / (6 mol/L × 1000 mL/L) ≈ 0.0014 mL
Therefore, approximately 0.0014 milliliters (or 1.4 microliters) of 6M HCl solution are required to react with 0.10g of Mg. Note that this volume is extremely small, practically unmeasurable due to the limited precision of most laboratory equipment.