Barium sulfate is listed as insoluble on solubility tables. It does, however, dissolve to a small extent. Its solubility at 50 'C is 0.00034g in 100. g of water. Express this solubility in parts per million

-I know the equation is
ppm= (grams of solute/L of solution) x 10^6

Are you sure about that formula? I think it may be (g solute/mL)*10^6.

I think you are looking at 3.4 ppm which you won't get if you use your formula.
I use ppm = mg/L.

put the aids in the anus

omigawd jamal that doesn tevennnn help at all. u shouldnt do tis no i cat even do mh hw.

first of all the formula is wrong the formula u used was for molarity. this is the correct formula ppm= grams of solute/ grams of solution x 10^6 bob that formula of yours is also wrong

To express the solubility of barium sulfate in parts per million (ppm), we need to convert the given solubility from grams per liter (g/L) to grams per million grams of the solution (g/g). Here's how you can do it:

Step 1: Convert the solubility from grams per 100 g of water to grams per liter of water.
The solubility of barium sulfate at 50°C is given as 0.00034 g in 100 g of water. To convert this to grams per liter, we need to divide the amount of solute by the amount of liquid:
0.00034 g / 100 g = 0.0000034 g/g

Step 2: Convert grams per liter to grams per million grams.
Since 1 g/L is equivalent to 1 g/1000 g (1 kg), we can convert grams per liter to grams per million grams by multiple the result by 1 million (10^6):
0.0000034 g/g x 10^6 = 3.4 g/g

Therefore, the solubility of barium sulfate at 50°C is 3.4 grams per million grams of the solution, which can be expressed as 3.4 ppm.